#### Answer

$-i$ and $1-i$

#### Work Step by Step

The Conjugate Pairs Theorem says that if a polynomial has real coefficients, then any complex zeros occur in conjugate pairs. That is, if $a + bi$ is a zero then so is $a – bi$ and vice-versa.
Its degree is $4$, hence it has $4$ complex (including real) zeros. $2$ zeros are already given, hence there are only $2$ zeros left which are $-i$ and $1-i$ (the conjugates of $i$ and $1+i$, respectively) according to the Conjugate Pairs Theorem.